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Q: What number has 5 factors exactly between 10 and 30?

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12

Any number of the form a*b^4 where a and b are different prime numbers, or c^9 where c is a prime, will have exactly 10 factors.

48

45

80

Any number n=q1q2...q10 with qi a prime number

Exactly halfway between them is 10.15.

no because every number is multiplied by 1 and it equals the same as the number...yay:D

How about 10 whose factors are 1 2 5 and 10

48 has 10 factors.

12

48 has ten factors, 60 and 72 have twelve apiece, 80 is the next one with exactly ten.

It's a multiple of 5, a multiple of 6 (since it's between twin primes), and less than 50. The only possibility is 30. To check: The factors of 30 are 1, 2, 3, 5, 6, 10, 15, and 30

The factors of 81 that are between 2 and 10 are 3 and 9.

48, 80 and 112 all have exactly 10 factors.

The first number to have exactly 10 divisors is 48.

To have an odd number of factors, the number must be a square. The only squares between 80 and 100 ()inclusive) are 81 and 100 but 81 does not have a factor of 5, and 100 has 9 factors. Thus the problem (as stated) has no solution. The numbers which have a factor of 5 must end in 0 or 5; the only numbers between 80 and 100 (inclusive) which match this criteria are {80, 85, 90, 95, 100}, which have {10, 4, 12, 4, 9} respectively. If you meant 3 PROPER factors (ie all the factors excluding the number itself), then 85 and 95 both have 3 proper factors.

30: 1, 2, 3, 5, 6, 10, 15, 30

10 is a factor that has four ; 1 , 2 , 5 , & 10

5, 10, 15 and 20 have five as a factor. The number 16 has five factors.

16, with factors 1, 2, 4, 8 and 16.

48 has the most factors; it has 10 factors: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

3 x 4 = 12

the answer would seem to be ten.

Any number between 30 and 40 can be a factor. The common factors of 30 and 40 are 1, 2, 5 and 10.